Math, asked by ayushghosh664, 3 days ago

In a town, there was an orphanage. Maria and Rohan of grade IX distributed 100 clothes together in that orphanage. Now, help their friend, Srijita to find the answers to the following questions:
If Maria has distributed 3 times the number of cloths distributed by

Rohan then, how many clothes were distributed by Maria?​

Answers

Answered by pankajvarshney151179
0

Answer:

Donation by each student No. of students donated

Cumulative frequency

5 15 15

7 15 30

10 20 50

15 16 66

20 14 80

To find the mean we will add up total cost of packets , then divide by total number of packets.

So,

Mean =

(15+15+20+16+14)

(5×15+7×15+10×20+15×16+20×14)

Mean =(75+105+200+240+280)/80=900/80=11.26

As we can see that the donation of greatest number of student is Rs. 10 each, so the mode will be 10

As we can see there are 80 students arranged in increasing order of their respective donations. So, the middle one will be (80)/2=40

th

and 41

st

student in the list.

So, the median will be the donation by student corresponding to cumulative frequency just greater or equal to 40 and 41 , i.e., 10

Therefore , median is 10

Step-by-step explanation:

Donation by each student No. of students donated

Cumulative frequency

5 15 15

7 15 30

10 20 50

15 16 66

20 14 80

To find the mean we will add up total cost of packets , then divide by total number of packets.

So,

Mean =

(15+15+20+16+14)

(5×15+7×15+10×20+15×16+20×14)

Mean =(75+105+200+240+280)/80=900/80=11.26

As we can see that the donation of greatest number of student is Rs. 10 each, so the mode will be 10

As we can see there are 80 students arranged in increasing order of their respective donations. So, the middle one will be (80)/2=40

th

and 41

st

student in the list.

So, the median will be the donation by student corresponding to cumulative frequency just greater or equal to 40 and 41 , i.e., 10

Therefore , median is 10

Answered by aradhanabaghele
0

Answer:

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Step-by-step explanation:

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