Question

In a train of 10000 families it was found that 40% family buy the newspaper A , 20% buy the newspaper B , 10% buy the newspaper C , 5% family buy the newpaper A and B , 3% buy the newspaper B and C , 4% buy the newspaper A and C if 2% buy all newspape. find number of family in which buy A only, B only and none od A,B,C

Answer 1

hello


given 40%+20%+10%+5%+3%+4%2%=84%

so , 100 % - 84% = 16%.

10,000x16% = 1600.

1600 family didn't buy any newspaper.

10,000 - 1600 =8400

8400 x 40/100 = 3360

3360 family buy only A newspaper

8400-3360= 5040

5040 x 20/100 = 1008

1008 family buy only B newspaper ..

hope it helps you.