in a traingel one angel is 60° andthe measure of one of the other two angels is half of the other .Find the measure of the smallest angle of the triangle.
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Let the two angles be x and x/2
× + ×/2 + 60° =180°
2x+x/2= 180°-60°
3x/2=120°
3x=120°×2
3x =240°
x=240°/3
x=80°
So the smallest angle is 40°
× + ×/2 + 60° =180°
2x+x/2= 180°-60°
3x/2=120°
3x=120°×2
3x =240°
x=240°/3
x=80°
So the smallest angle is 40°
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