In a trangle ABC angleA=100angle B=100what willbe the third angle
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a=100° ( Angle around the
B=100° point = 360° )
C=?
As per the problem
A+B+C = 360°
100°+100°+C = 360° {200° transfer
200°+C = 360° to rhs side}
C = 360°-200°
C = 160°
Therefore the angle of C= 160°
B=100° point = 360° )
C=?
As per the problem
A+B+C = 360°
100°+100°+C = 360° {200° transfer
200°+C = 360° to rhs side}
C = 360°-200°
C = 160°
Therefore the angle of C= 160°
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