In a transformer the copper losses at full load are 50 watts. At 60% of the full load the copper losses will be?
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The copper losses are equal to the iron losses when the load (current) is 80% of full load. Since copper losses are proportional to the square of current, to scale up from 80% load to 100% load multiply the losses at 80% load by the square of the 100/80 increase in load
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