In a transformer without any loss in power, there are 5000 turns in the primary and 250 turns in the secondary. The primary voltage is 120 V and the primary current is 0.1 A. Find the voltage and current in the secondary?
Answers
Answered by
2
Explanation:
N
p
=5000
N
s
=250
V
p
=120
I
p
=0.1A
V
p
V
s
=
N
p
N
s
V
s
=
N
p
N
s
×V
p
=
5000
2500
×120=6V
V
p
V
s
=
I
s
I
p
I
s
=
V
s
I
p
×V
p
=
6
0.1
×120=2A
Answered by
0
Here's your answer dude ✅:
⟹So, from this, we can say that the total induced voltage in each winding will be directly proportional to the number of turns in that particular winding. ... Therefore, the secondary voltage of the coil will be $6V$
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