Question

In a transistor circuit if emitter current is 10mA and base current is 2mA find collector current alpha and beta.​

Answer 1

0.5 mA

Given that:

α=0.95

Emitter current, I

e

=10 mA

We have:

α=

I

e

I

c

I

c

=α×I

e

I

c

=0.95×10=9.5 mA

Also,

I

e

=I

b

+I

c

10=I

b

+9.5

I

b

=0.5 mA

Answer 2

Answer: Therefore, the collector current is approximately 48.02 mA, α is 0.96 or 96%, and β is 24.

Explanation: Given that the emitter current (Ie) is 10 mA and the base current (Ib) is 2 mA.

We know that the relationship between α and β is given by α = β / (1 + β).

Let's use the equation for the collector current (Ic) in terms of β:

Ic = β × Ib + Ie

Substituting the given values, we get:

Ic = β × 2 mA + 10 mA

Ic = 2β + 10 mA

To find the value of β, we can use the equation β = Ic / Ib. Substituting the given values, we get:

β = Ic / Ib

β = (2β + 10 mA) / 2 mA

β = 1000 × (2β + 10 mA)

Simplifying the equation, we get:

2β = 48

β = 24

Now we can find the value of α using the equation α = β / (1 + β):

α = β / (1 + β)

α = 24 / (1 + 24)

α = 0.96 or 96%

Finally, we can find the value of collector current (Ic) using the equation we derived earlier:

Ic = 2β + 10 mA

Ic = 2 × 24 + 10 mA

Ic = 48.02 mA

Therefore, the collector current is approximately 48.02 mA, α is 0.96 or 96%, and β is 24.