Question

In a trapezium ABCD a line EF cuts diagonal AC at O such that AO/OC=2/3 and EF is parallel to BC. In what ratio does EF cut AB and CD

Answer 1

Answer:

AE

=

BE

DE

=

2

1

In ΔABD and ΔBEC

∠BEC=∠AED

EC

AE

=

EB

DE

∴ΔBEC∼ΔAED

∴

EC

AE

=

BE

EB

=

BC

AD

=

2

1

2AD=BC

BC=2×4=8