In a trapezium ABCD a line EF cuts diagonal AC at O such that AO/OC=2/3 and EF is parallel to BC. In what ratio does EF cut AB and CD
Answers
Answered by
1
Answer:
AE
=
BE
DE
=
2
1
In ΔABD and ΔBEC
∠BEC=∠AED
EC
AE
=
EB
DE
∴ΔBEC∼ΔAED
∴
EC
AE
=
BE
EB
=
BC
AD
=
2
1
2AD=BC
BC=2×4=8
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