Question

. In a trapezium ABCD, AB= 58 cm, DC = 42 cm, BC = 17 cm and AD = 17 cm. Find its area.

Answer 1

we know area of trapezium =1/2 (h)(ab+CD)
height of trapezium is 15cm
area = 1/2(15)(58+42).
=1/2(15)(100)
=1500/2
=750