Question

in a trapezium ABCD AB||CD and AD perpendicular AB. also a b = 16, DC= BC =10m
find the area of trapezium??
pls solve this question...​

Answer 1

Answer:

Area of trap=

2

1

×(AB+CD)×DE

In right △AED,DE=

AD

2

+AE

2

AE=AB−BE=16−8=8m

∴DE=

(17)

2

−(8)

2

=

284−64

=

225

=15m

Hence, ar. trap=

2

1

×(8+16)×15=12×15=180m

2