Math, asked by vi7dyanAtheaSen, 1 year ago

In a trapezium ABCD, AB||CD and DC=3AB. EF||AB intersects DA and CB at E and F such that BF divided by FC = 2divided by3. prove that 3DC=5EF

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Answered by kvnmurty

1

This problem is dealt in http://brainly.in/question/743820

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