In a trapezium ABCD, AB||CD. If angle A =63°, angle C = 124°, find angle B & D..
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◇GIVEN:
- IN A TRAPEZIUM ABCD , AB||CD ∠A = 63° and ∠C = 124°
◇TO FIND :
- ∠B and ∠D
◇SOLUTION:
I HAVE EXTENDED LINES AB , BC ,CD AND AD
SUCH THAT AD AND BC ARE TRANSVERSALS AND AB AND CD ARE PARLLEL LINES
∠A + ∠D = 180° [ CO- INTERIOR ANGLES ]
63° + ∠D = 180° => ∠D = 180° - 63°
=> ∠D = 117°
IN THE SAME WAY ∠B + ∠C = 180° [∵ CO - INTERIOR ANGLES]
=> ∠B + 124° = 180°
=> ∠B = 180° - 124°
=> ∠B = 56°
∴ ∠B = 56° , ∠D = 117°
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