Question

In a Trapezium ABCD AB || CD. If angle B = 95° and Angle D = 48°, find the other two angles

Answer 1

A+B=180 degree (co-interior angles)
A+95°=180°
A=180°-95°
A=85°
D+C=180°
48°+C=180°
C=180°-48°
C=132°

Answer 2

Given: AB II CD
            Angle B= 95
           Angle D= 48
To find: Angle A and Angle C=?
Solution: AB II CD...(given), on transversal AD
                 Angle A + Angle D= 180...( Interior angles are supplementary)
                 .: Angle A + 48= 180  (given)
                Angle A = 180 - 48
                               = 132
Similarly, AB II CD, On transversal BC
Angle B + Angle D= 180...(Interior angles are supplementary)
.: 95 + Angle D = 180   (Given)
.: Angle D = 180 - 95
                  = 85