Math, asked by lumadevkota04, 5 hours ago

In a trapezium ABCD, AB || CD, the point P and the point Q lie on the side AB and BC respectively. PQ || AC, prove that area of triangle ADP = area of Triangle ACQ

Answers

Answered by singhprince0457
0

Answer:

Step-by-step explanation:

Prove that the diagonals of a parallelogram divide it into four triangles of ... (i) area of ∆OAB + area of ∆OCD = area of || gm ABCD. ... If E, F, G and H are mid-points of the sides AB, BC, CD and DA respectively of a ... P, Q are any two points ... (b) In the figure (2) given below, DE is drawn parallel to the diagonal AC of the.

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