Question

in a trapezium ABCD, AB//DC, AB = 30 CM , BC=15 CM, DC=44 CM andAD=13 CM. find the area of trapezium. ​

Answer 1

Step-by-step explanation:

area of trapezium = 1/2 x sum of parallel sides x height

=1/2 x (30+44) x h

where we need to find height -

BC=15

ec=?

Ec+df+fe=44cm

=ec+df=44-30 as AB is equaltoef

ec=7cm

area of trapezium=1/2 x(30+44) x15

=1/2x74x15

=37x15

=555cm sq.

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