Question

in a trapezium abcd ab//dc,bcd 52 and adc 62 tel what is abd and cbd

Answer 1

Since, AB // DC

∴ ∠BCD + ∠DCB = 180° (co-interior angles)

⇒ 52° + ∠DCB = 180°

⇒ ∠DCB = 180° - 52°

⇒ ∠DCB = 128°

Similarly,

⇒ ∠ADC + ∠DAB = 180° (co-interior angles)

∴ ∠DAB + 62° = 180°

⇒ ∠DAB = 180° - 62°

⇒ ∠DAB = 118°

ANS: ∠DCB = 128° and ∠DAB = 118°

Hope it will help you......