in a trapezium ABCD AB||DC if P is the midpoint of AD then prove that the line drawn through P and parallel to AB bisects BC.
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Step-by-step explanation:
In triangle ADC,
P is midpoint of AD. (Given)
PR||DC (Given)
So,
R is midpoint of AC (By mid point theorem)
Now,
In triangle ACB,
R is midpoint of AC (proved above)
AB || RQ ( Given)
So,
Q is midpoint of BC ( By midpoint theorem)
Therefore,
BQ=QC
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