Math, asked by Anisha2020, 9 months ago

In a trapezium ABCD, AB II CD, AC & BD are diagnols that intersect at O. Prove that AO×OD=BO×OC.

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Answered by Anonymous

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Answer:

AO/BO = CO/DO Given: ABCD is a trapezium where AB II DC & diagonals AC & BD intersect at O To prove: AO/BO=CO/DO ...

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