Question

In a trapezium ABCD, AB is parallel to CD, A: D=7:2 and
C=4:5. Find the angles of the trapezium.​

Answer 1

Answer:

answer is 60 degree each side...

Step-by-step explanation:

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Answer 2

Given:

AB is parallel to DC

, BC = 5 cm, CD = 4 cm and AD = 5 cm.

Steps for construction:

Step 1 : Draw a rough diagram and mark the given measurements. Draw

CE ∥ DA

. Now AECD is a parallelogram. ∴ EC = 5 cm, AE = DC = 4 cm, EB = 3cm.

Step 2 : Draw a line segment AB = 7 cm.

Step 3 : Mark E on AB

such that AE = 4 cm . [ ∵ DC = 4 cm ]

Step 4 : With B and E as centres draw two arcs of radius 5 cm and let them cut at C.

Step 5 : With B as centre and radius 6 cm draw an arc cutting

BY at C.

Step 6 : With C and A as centres and with 4 cm and 5 cm as radii draw two arcs. Let them cut at D.

Step 7 : Join

AD and CD

ABCD is the required trapezium.

Step 8 : From D draw

DF⊥ AB

and measure the length of DF. DF = h = 4.8 cm, AB = a = 7 cm, CD = b = 4 cm.

Calculation of area:In the trapezium ABCD, a = 7 cm, b = 4 cm and h = 4.8 cm.

$\implies \frac{1}{2} (4.8)(7 + 4)$

$\implies \frac{1}{2} \times 4.8 \times 11$

$\implies \: 2.4 \times 11$

$\implies26.4 {cm}^{2}$