Question

In a trapezium ABCD , AB is parallel to CD and the diagonals intersect each other at O. What is the ratio of OA and OC ?​

Answer 1

Step-by-step explanation:

∆AOB~∆COD(AA similarity)

So AO/CO=AB/CD=OB/OD

Answer 2

Answer:

Theorem: Given a trapezium ABCD with parallel sides AB and CD, let O be the intersection of the diagonals AC and BD. If the ratio r = AB/CD, then the diagonals are divided by this same ratio: AO/CO = BO/DO = r.