in a trapezium ABCD, AB is parallel yo DC , if DC=2AB, show that the point of intersection of two diagonals is a point of trisection
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Let the point of intersection of the two diagonals AC and BD be O.
The ΔAOB and ΔDOC are similar. The corresponding sides AO || CO, BO || DO and AB || CD.
CD / AB = 2 = CO / OA = DO / OB
So OC = 2 OA and OD = 2 OB
So O is the point of trisection of the diagonals AC and BD.
The ΔAOB and ΔDOC are similar. The corresponding sides AO || CO, BO || DO and AB || CD.
CD / AB = 2 = CO / OA = DO / OB
So OC = 2 OA and OD = 2 OB
So O is the point of trisection of the diagonals AC and BD.
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