in a trapezium ABCD ab parallel to dc ab is equal to 30 cm BC is equal to 15 CM BC is equal to 44 cm and ad is equal to 13 centimetre find the area of trapezium.
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Answer:
trapezium ABCD
AB∥CD,
AB=30cm and CD=44cm, AD=13cm,BC=15cm.
semi-perimeter =
2
30+44+13+15
=51
area of trapezium =
(s−a)(s−b)(s−a−c)(s−a−d)
⋅
(b−a)
(a+b)
where a and b are two parallel sides and b > a and c and d are non-parallel sides
s=
2
a+b+c+d
=51
area of trapezium ABCD=
44−30
30+44
⋅
(51−30)⋅7(51−30−13)⋅(51−30−15)
=
14
74
⋅
21⋅7⋅8⋅6
=
7
37
⋅7
3⋅3⋅2⋅8
=37×3×4=37×12=444cm
2
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