Question

in a trapezium ABCD ab parallel to dc and ac, BD are intersecting at the point o then show that oa/oc=bo/do
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Answer 1

Step-by-step explanation:

In ∆AOB and ∆COD,

angle AOB is congruent with angle COD ----- vertically opposite angles ( equation 1 )

angle ABO is congruent with angle CDO -----

alternate angles ( equation 2 )

∆AOB ~ ∆COD ----- by AA test of similarity ( from equation 1 and 2 )

AO/CO = OB/OD ------ c.s.s.t.

i.e. OA/OC = BO/DO

Answer 2

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