In a trapezium ABCD,angle A:D=3:2and angle B:C=4:5.Find the angles of trapezium
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a and d together will be 180
3x+2x=5x=180
x=180/5=36
108and72
b and c together will be of 180
4x+5x=180
9x=180
x=180/9=20
80 and 100
the sum will be 180 of pairs because they are on one side of transversal which will cut parallel lines
3x+2x=5x=180
x=180/5=36
108and72
b and c together will be of 180
4x+5x=180
9x=180
x=180/9=20
80 and 100
the sum will be 180 of pairs because they are on one side of transversal which will cut parallel lines
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