In a trapezium abcd if ad=15 cm and bc =15 and ab = 25 find area of abcd
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Given :-
- Shape = Trapezium
- First Parallel Side = 15cm
- Second Parallel Side = 15cm
- Height of the Trapezium = 25cm
To Find :-
- Area of the Trapezium.
Solution :-
⇒ Area = ½ × Height × sum of parallel sides
⇒ Area = ½ × 25 × ( 15 + 15 )
⇒ Area = ½ × 25 × 30
⇒ Area = 25 × 15
⇒ Area of Trapezium = 375cm²
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Therefore, Area of Trapezium is 375cm²
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★ Additional Info :
Formulas Related to Area :
- Area of Square = Side x Side
- Area of Rectangle = Length × Breadth
- Area of Triangle = ½ × base x height
- Area of parallelogram = base x height
- Area of circle = πr²
- Area of Rhombus = ½ × product of its diagonals
- Area of Trapezium = ½ × height × sum of parallel sides
- Area of Polygon = sum of the area of all regions into which it is divided
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