Question

in a trapezium ABCD in which AB is parallel to CD x is the midpoint of diagonal ac and y is the midpoint of bd if ac= 8 and bd=3 then find CD

Answer 1

Answer:

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Answer 2

☯ Correct Question:-

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• in a trapezium ABCD in which AB is parallel to CD x is the midpoint of diagonal ac and y is the midpoint of bd if ac= 8 and bd=3 then find CD

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☯ Solution:-

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• ABCD is a trapezium and E, F are mid-points of diagonal AC and BD

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• AB | CD one par of opposite sideis parallel in trapezium]

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In ACDF and AGBF

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• DF = BF [point of diagonal BD]

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• DCF = BCGF |DC || GB and CG

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Since, F is mid- is a transversal

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• LCDF = LGBF [DC | GB and BDis a transversal]

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• ACD ∆ GBF [By ASAcongruence rule]

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CD = GB [C.Pc.T]-(1)

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• In ACAG, the points E and F are themid-points of AC and CG respectively.

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== > EF = 1/2 (AG)

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$Therefore \;CD = 1/2 AG$

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