Question

In a trapezium ABCD, OC and OD are the bisectors of /C and /D. Find the measure of /ABCD and /DAB
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Answer 1

Answer:

Step-by-step explanation:

Given OD and OC are bisectors of ∠DCB  AND ∠CDA , respectively .

So, ∠OCB = 30° , ∠ADO = 50° AND AB║CD

In a trapezium,

                               ∠B + ∠C = 180°

⇒ ∠B + DCO + ∠OCB = 180°

⇒ ∠B + 30° + 30° = 180°

⇒∠B = 180° - 60° = 120°

∴ ∠B = 120°

Similarly , ∠A + ∠D = 180°

⇒ ∠A + ∠ODA + ∠ODC = 180°

⇒ ∠A + 50° + 50° = 180°

∴ ∠A = 180°- 100° = 80°