Question

In a trapezium ABCD , side AB is parallel to side DC ; and the diagonals AC and BD intersect each other at point P . Prove that : (i) triangle APB is similar to triangle CPD . (ii). PA×PD =PB× PC

Answer 1

i )by sss congrency....
ii) yes....

Answer 2

don't know 2nd one
I'm sry for that
hope the 1st one helps u out