In a trapezium ABCD , side AB is parallel to side DC ; and the diagonals AC and BD intersect each other at point P . Prove that : (i) triangle APB is similar to triangle CPD . (ii). PA×PD =PB× PC
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Answered by
4
i )by sss congrency....
ii) yes....
ii) yes....
Answered by
15
don't know 2nd one
I'm sry for that
hope the 1st one helps u out
I'm sry for that
hope the 1st one helps u out
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