Question

In a trapezium ABCD , side AB is parallel to side DC . If angle A=x°and angle D=(3x-20)° ; find the value of x

Answer 1

as ab is parallel to CD and ad is a transversal

angle A + angle D =180 (sum of angles on the same side of transversal is 180)

x+ 3x-20= 180

4x-20= 180

4x=180+20

4x= 200

x=200/4

x=50

Answer 2

The value of x is 50.

Step-by-step explanation:

Given information: In trapezium ABCD, AB║DC, ∠A=x° and ∠D=(3x-20)°.

$\angle A+\angle D=180$                  (Same sided interior angles are supplementary)

$x+(3x-20)=180$

$4x-20=180$

$4x=180+20$

$4x=200$

Divide both sides by 4.

$x=50$

Therefore, the value of x is 50.

#Learn more

Find the value of x in the trapezium ABCD where AB and CD are parallel sides and angle A = x-20° , angle D = x+40°.

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