Question

In a trapezium ABCD ,side AB ∥ side DC. Diagonals AC and BD cut each other at O. If AB = 15,

DC=10, OA=9 then find OC.​

Answer 1

Given :- In a trapezium ABCD ,side AB ∥ side DC. Diagonals AC and BD cut each other at O. If AB = 15, DC=10, OA=9 then find OC.

Answer :-

we know that,

• The diagonals of a trapezium divide each other proportionally.

so,

→ AO / OC = BO / OD = AB / DC .

putting values we get,

→ AB / DC = AO / OC

→ 15/10 = 9 / OC

→ 3/2 = 9 / OC

→ OC = 3 * 2 = 6 cm (Ans.)

Learn more :-

ABCD is a rhombus with A = 60° , BC = (3x+5)cm , CD =(6x-10)cm and AC =(3y-1)cm. Find

x and y.

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3.

In the fig, AB || CD,FIND x.(Hint:Prove that AOB-COD).

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