In a trapezium ABCD, the two non-parallel sides are given as AD and BC. If AD = BC and DAB = CBA. Then prove that AC = BD and
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AC = BD , by SAS congruency criteria.
If you see, triangle DAB and triangle CAB
Angle DAB = Angle CAB ( Given )
AD = BC ( Given)
AB = AB ( Common in both the triangles )
So by SAS congruency criterian
Triangle DAB CONGRUENT TO Triangle CAB
SO by CPCT , we can say that
AC = BD
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