Question

In a trapezium ABCD with AB || DC and the diagonals intersect at a point o, If DO = 3x – 19,0B = x-5, CO = x - 3 and AO = 3, then the value of x is_____________​

Answer 1

Answer:

x=8,11

Step-by-step explanation:

AB∥CD [ Given ]

∴ Quadrilateral ABCD is a trapezium.

∴

CO

AO

=

DO

BO

[ Diagonals of trapezium divides each other proportionally ]

⇒

x−3

3x−19

=

4

x−4

⇒ (3x−19)(4)=(x−4)(x−3)

⇒ 12x−76=x

2

−3x−4x+12

⇒ x

2

−19x+88=0

⇒ (x−8)(x−11)=0

∴ x=8 or x=11