Question

In a trapezium, if distance between parallel sides is 8cm, and lengths of the parallel sides are 13cm and 9cm respectively then find the area of the trapezium​

Answer 1

Answer:

Correct option is

A

51 cm

2

Length of parallel sides=8 cm, 9 cm

Distance between parallel sides=6 cm

Area =

2

1

(distance between parallel sides)× (sum of parallel sides)

=

2

1

×6×(8+9)

=3×17=51

Answer 2

$\star \; {\underline{\boxed{\red{\pmb{\frak{ \; Given\; \; :- }}}}}}$

• Distance Between Parellel Sides = 8cm

• Lenght of Parellel Sides = 13cm and 9cm.

$\begin{gathered} \\ \qquad{\rule{200pt}{2pt}} \end{gathered}$

$\star \; {\underline{\boxed{\pink{\pmb{\frak{ \; To \; Find\; :- }}}}}}$

• Area of Trapezium = ?

$\begin{gathered} \\ \qquad{\rule{200pt}{2pt}} \end{gathered}$

$\begin{gathered} \\ \\ \end{gathered}\star \;{\underline{\boxed{\green{\pmb{\frak{ \;Solution\; :- }}}}}}⋆$

$\maltese$Formula Used :

• ${\underline{\boxed{ \pmb{ \pmb{ \pmb{\pmb{\sf{ Trapezium \; _{(Area)}=\dfrac{1}{2}×(a+b)h}}}}}}}}$

$\begin{gathered} \\ \qquad{\rule{200pt}{2pt}} \end{gathered}$

Where :

• H = Height

$\maltese$Calclating The Area :

$\qquad \; \dashrightarrow \; \; \sf { Trapezium \; _{Area}=\dfrac{1}{2}×(a+b)h}$

$\qquad \; \dashrightarrow \; \; \sf { Trapezium \; _{(Area)}=\dfrac{1}{2}×(13 + 9)8}$

$\qquad \; \dashrightarrow \; \; \sf { Trapezium \; _{(Area)}=\dfrac{1}{2}×(22)8}$

$\qquad \; \dashrightarrow \; \; \sf { Trapezium \; _{(Area)}=\dfrac{1}{2}×22 \times 8} \\[/</p><p>tex]</p><p></p><p>[tex]$

$\qquad \; \dashrightarrow \; \; \sf { Trapezium \; _{(Area)}=\dfrac{1}{2}×176}$

$\qquad \; \dashrightarrow \; \; \sf { Trapezium \; _{(Area)}=\dfrac{176}{2}}$

$\qquad \; \dashrightarrow \; \; \sf { Trapezium \; _{(Area)}= \cancel\dfrac{176}{2}}$

$\qquad \; {\dashrightarrow\; \; {\underline{\boxed{ \pmb{ \pmb{\pmb{\sf{ Trapezium \; _{Area} = 88cm {}^{2} \; cm }}}}} \; {\red{\pmb{\bigstar}}}}}}$

$\therefore$ Area of Trapezium is $\bf{88^2}$

$\begin{gathered} \\ \qquad{\rule{200pt}{2pt}} \end{gathered}$