In a trapezium if the sum of the parallel sides is 10 cm and the area is 140 sq. cm,
then the height is
(i) 7cm
(ii) 40 cm
(iii) 14 cm
(jv) 28 cm.
Hey Mate Please help me to answer this question because I am in a critical situation. Plzz
Answers
Answer:
trapezium area= 1/2×sum of parallel sides ×height
therefore,140=1/2×10×h
140=5h
140/5=h
therefore,h=28
this is your answer
please mark me as brainliest answer
Given : In a trapezium the sum of the parallel sides is 10 cm and the area is 140 sq. cm,
To Find : the height of trapezium
(i) 7cm
(ii) 40 cm
(iii) 14 cm
(jv) 28 cm.
Solution :
Area of trapezium = (1/2) ( sum of parallel side) * distance between parallel side
=> 140 = (1/2) * ( 10) * height
=> 140 = 5 * height
=> height = 140/5
=> height = 28 cm
Height of trapezium is 28 cm
Learn More:
If the area of a trapezium with parallel sides of length 30 cm and 23 ...
brainly.in/question/4717262
Find the area of trapezium in which parallel sides are of length 5 cm ...
brainly.in/question/3877026