Question

In a trapezium-shaped field, one of the parallel sides is twice the other. If the area of the field is 9450 m2 and the perpendicular distance between the two parallel sides is 84 m, find the length of the longer of the parallel sides.
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Answer 1

Answer:

longer side=150 m

Step-by-step explanation:

let the shorter side be x

and the longer side=2x      height=84m

area of trapezium=sum of parallel sides*height /2

area=9450m^2

9450=3x*84/2

        =3x*42

        =126x

x=9450/126

 = 75

therefore longer side which is equal to 2x is 150 m long

Answer 2

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Let length of first parallel side X

Length of other parallel side is 2X

Area of trapezium= 9450 m^2

Let Height (h) =84 m

We know that area of trapezium is 1/2× (sum of parallel sides) × height

Therefore Area of trapezium is =

$\frac{1}{2} \times (sum \: of \: parallel \: sides) \times \times height$

$84 = 9450 {cm}^{2} \\ \frac{1}{2} \times (x + 2x) \times 84 = 9450 \\ (3x) \times 42 = 9450 \\ 126x = 9450 \\ 2x + 6 = \frac{9450}{126} = 75 \\ x = 17$

Since, Length of the parallel sides is X=75 m and 2X = 150 m.

Therefore length of the longest is 150 m.

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