Math, asked by nehasingh7081092734, 1 year ago

In a trapezium, the length of one of the
parallel sides is 2.5 cm more than the
other. Find the lengths of the parallel sides
if the height is 6 cm and area is 115.5 cm2.​

Answers

Answered by Esther24
21

Answer:

18cm

  • Step-by-step explanation:

Ans= 18cm

Area= 115.5 cm^2

that is ,

1/2* height*( sum of the parallel sides) = 115.5 cm^2

Let one side =xcm

and another side =( x+2.5 )cm

1/2* 6cm* ( x+x+2.5)cm= 115.5 cm^2

3cm * (2x+2.5) cm= 115.5cm^2

2x+ 2.5 cm= 115.5cm^2/3cm

=38.5cm

2x =(38.5 - 2.5)cm

2x= 36cm

x= 18cm

another side = 18+2 .5 = 20.5 cm

Attachments:
Answered by subhojitsarkar0838
4

Answer:

In trapezium, the length of one of the the parallel side is 2.5cm more than the other.

Let,the side be "x"

Now,the length of one side =x

Then the length of other side =x+2.5cm

The height of trepezium=6cm

The area of trapezium=115.5cm^2

115.5cm^2=1/2×6×(x+x+2.5)

115.5cm^2=1/2×6×(2x+2.5)

2x+2.5=115.5/3

2x+2.5=38.5

2x=38.5-2.5cm

2x=36cm

x=36/2cm

x=18

:. The length of one side =18cm(answer)

:.The length of other side =18+2.5cm

=20.5(answer)

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