Question

In a trapezium, the lengths of parallel sides are 18 and 26 unit. Then the length of line joining the midpoints of the diagonal of the trapezium is a)8 unit b)4 unit c)2 unit d)0 unit​

Answer 1

Given :- In a trapezium, the lengths of parallel sides are 18 and 26 unit. Then the length of line joining the midpoints of the diagonal of the trapezium is :-

a)8 unit

b)4 unit

c)2 unit

d) 10 unit

Solution :-

we know that,

• The length of line joining the midpoints of the diagonal of the trapezium is half of difference of parallel sides.

So,

from image given that,

• ABCD is a trapezium.
• AB || CD .
• AB = 18 unit .
• CD = 26 unit .
• AC and BD are diagonals of Trapezium.
• To Find :- EF .

Than,

→ EF = (CD - AB)/2 {The length of line joining the midpoints of the diagonal of the trapezium is half of difference of parallel sides.}

→ 2EF = CD - AB

→ 2EF = 26 - 18

→ 2EF = 8

dividing both sides by 2,

→ EF = 4 units. (Ans.) (Option b).

Hence, the length of line joining the midpoints of the diagonal of the trapezium is 4 units.

Learn more :-

ABCD is a rhombus with A = 60° , BC = (3x+5)cm , CD =(6x-10)cm and AC =(3y-1)cm. Find

x and y.

please urgent please

n...

https://brainly.in/question/25624939

3.

In the fig, AB || CD,FIND x.(Hint:Prove that AOB-COD).

https://brainly.in/question/17942233

Answer 2

Answer:

Hope this may be helpful