Question

in a trapezium the parallel sides are 4cm and 5cm and distance between them is 6cm find its area​

Answer 1

Answer:

27cm²

Step-by-step explanation:

Area of trapezium = 1/2 x h x (AB + DC)

                               =1/2 x 6 x (4+5)

                               =1/2 x 6 x 9

                               =3 x 9

                               =27cm²

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Answer 2

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In a trapezium the parallel sides are 4cm and 5cm and distance between them is 6cm find its area.

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➡Area of trapezium is 27cm²

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• Parallel sides of trapezium are 4cm and 5cm
• Height = 6cm

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• Area of trapezium

$\bf {\underline {\underline{✤ ƑƠƦMƲLƛ \: \: ƬƠ \: ƁЄ \: \: ƲƧЄƊ}}}$

Area of trapezium

$\bf \purple{ \frac{1}{2} \times sum \: of \: ll \: sides \times h}$

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Area of trapezium =

$\bf \frac{1}{2} \times sum \: of \: ll \: sides \times h$

$\bf \implies \frac{1}{2} (4 + 5) \times 6$

$\bf \implies \frac{1}{\cancel2} \times 9 \times \cancel 6 \: 3$

$\bf \implies 9 \times 3$

$\bf \implies {27cm}^{2}$

Therefore, Area of Trapezium is 27cm².

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