Question

in a trapezium two non parallel sides are equal in length each being 5 unit the parallel sides are at a distance 3 unit apart if the smaller of the parallel is of length 2 units find the sum of diagonals of trapezium​

Answer 1

Answer:

Correct Answer:

B) 65–√ units

Step-by-step explanation:

In △BCF, by Pythagoras theorem,

(5)2=(3)2+(BF)2

BF=4 cm

AB=2+4+4=10 cm

Now, in △ACF, AC2=CF2+FA2

=> AC2=32+62 => AC=45−−√cm

Similarly, BD = 45−−√cm

Sum of diagonals

=AC+BD= 45−−√+45−−√=245−−√=65–√cm