in a trapezium WXYZ , < Z = 3:2 and < X : <Y= 4 : 5 find the angles of the trapezium plz solve the question
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<W + <X +<Y + <Z = 360° (sum of all angles of a quadrilateral is 360°)
Lets take the angles as 3x, 2x, 4x and 5x.
Then, 3x +2x +4x +5x =360
14x = 360
x = 360
14
x = 25.7
2x = 51.4°
3x = 77.1°
4x = 102.8°
5x = 128.5°
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