Question

In a trepizem parallel sides are 12,8 and volume 60 .find the distance between two sides

Answer 1

Correct question :- In a trapezium, the parallel sides are 12 and 8 units. and it's area is 60 sq units. find the distance between the parallel sides.

Given :-

Parallel sides of the trapezium :-

• b1 = 12 units

• b2 = 8 units

Area of the trapezium = 60 sq. units

We know that,

1/2 × h (b1 + b2) = area of a trapezium

➡ 1/2 × h (b1 + b2) = 60 sq. units

➡ h (12 + 8) = 60 × 2

➡ 20h = 120

➡ h = 120/20

➡ h = 6

Hence, it's height is 6 units.

VERIFICATION :-

Area of the trapezium = 1/2 × h(b1 + b2)

= 1/2 × 6(12 + 8)

= 3 × 20

= 60 sq. units

Jence verified! the distance between the parallel sides of the trapezium is 6 units.

Answer 2

$\red {\huge {\underline{ \frak{Your \: answEr : }}}}$

$\green{\large{ \underline{\mathcal{\star \:Given : }}}}$

Parallel Sides of Trapezium :

• P1 = 12 cm
• P2 = 8 cm

Area of Trapezium = 60 cm²

$\green{\large{ \underline{\mathcal{\star \: To \: Find : }}}}$

• Find the Distance Between two Parallel Lines [ h ].

$\green{\large{ \underline{\mathcal{\star \: Solution : }}}}$

$\boxed {\bold{Area \: of \: Trapezium = \frac{1}{2} \times h(p1 + p2)}}$

$\large\implies\bold{60 = \frac{1}{2} \times h(12 + 8)}$

$\large\implies\bold{60 \times 2 = h(12 + 8)}$

$\large\implies\bold{h = \frac{120}{20} }$

$\purple{\large\implies\bold{h = 6 \: cm}}$

$\huge{\red{\ddot{\smile}}}$