Question

In a tri. ABC where AB=AC and angle A = 50. then what is measure of C?

Answer 1

Since , AB=AC
so, <C=<B
There fore A+B+C=180°
By simplification <C=<B=65°

Answer 2

Bonjour, there your answer is __,

$answer$

Let, ABC is a triangle

where, AB=AC=x

$x + x + 50 = 180$

$2x + 50 = 180$

$2x = 180 - 50$

$2x = 130$

$x = \frac{130}{2}$

$x = 65$

So, B=C=65



Therefore angleC=65.

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