Question

In a
trianangle
PQR <P = 30°and<Q= <R find R
​

Answer 1

Answer:

75

180-30=150

150/2

75

angle R=75

Answer 2

Answer:

We know,

In a triangle sum of all the angles is

$= {180}^{o}$

And, it is given that

$angle \: p = {30}^{o} \: and \: angle \: q = angle \: r \\ which \: means \: the \: given \: traingle \: is \: an \: isoceles \: triangle \\ let \: angle \: q = angle \: r = x \\ now \\ angle \: p + angle \: q + \: angle \: r = {180}^{o} \\ {30}^{o} + x + x = {180}^{o} \\ 2x = {180}^{o} - {30}^{o} \\ x = {150}^{o} \div 2 \\ x = {75}^{o}$

angle R=75degree