Question

In a triange ABC, prove that AB + AC > 2AD, where AD is the median from A to BC..pls answer this one....

Answer 1

Hi friend ✋✋✋✋
--------------
Your answer
---------------------

In ∆ABC, AD is a median.

To prove : - AB + AC > 2AD

Now,
---------

AB > AD [Because, she's of a triangle are greater than is medians.]

Similarly,
--------------

AC > AD [Because, she's of a triangle are greater than is medians.]

Therefore,
------------------

AB + AC > AD + AD

=> AB + AC > 2AD

HOPE IT HELPS