Question

In a triangle (2, 3 ) (4,k )and (6, -3) are collinear find the value of k​

Answer 1

Answer:

the answer is in the attachment

Answer 2

Answer:

if the points are collinear

then

1/2 {2(k+3) + 4(-3-3)+ 6(3-k)} =0

→ 2k + 6 -24 + 18 - 6k = 0

→ -4k=0

→ k=0