Math, asked by renus0202, 8 months ago

In a triangle A is 5x-60, B=2x+40 and C=3x-80
find the value of each angle​

Answers

Answered by anu00916
4

5x-60+2x+40+3x-80=180

10x-100=180

10x=180-100

x=8°

A=5(8)-60=40-60=20

b=16+40:56

c=6-80:74

Answered by aarushi2007rawat
0

Answer:

The angles of a triangle are (2 x - 30°) (3x - 40°) and (5/2 + 10°). How do you find x and the answer?

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Sum of 3 angles of a triangle should be equal to 180°

So , sum of (2x-30°) , (3x-40°) and (5/2+10°) should be 180°

(2x-30) + (3x-40) + (5/2+10) = 180

5x - 30 - 40 + 10 + 5/2 = 180

5x - 60 + 5/2 = 180

5x = 180 + 60 - 5/2

5x = 240 - 5/2

5x = 475/2

x = 95/2

x = 47.5

Now the 3 angle of triangle are :

(2x-30) = 2*47.5 - 30 = 65°

(3x-40) = 3*47.5 - 40 = 102.5°

(5/2+10) = 12.5°

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