Question

 In a triangle ∠A=x, ∠B =3x and ∠C =x/2 Find the measure of ∠C. ​

Answer 1

Ina△ABC, (By angle sum property)

∠A+∠B+∠C=180

∘

∠C−∠B=9

⟹y−(3x−2)=9

∴y=7+3x

x+(3x−2)+y=180

∘

⟹4x−2+7+3x=180

∘

⟹x=25

∘

∴y=7+3×25=82

∘

∴∠A=x=25

∘

,B=3x−2=73

∘

∠C=y=82

∘

Answer 2

Here we are given that ∠A=x, ∠B =3x and ∠C =x/2

We have to find the value of ∠C

We know that sum of angles in a triangle is 180°

Therefore,

x + 3x + x/2 = 180

4.5 x = 180

x = 40

Now, ∠C = x/2

= 40/2

= 20

Hence, the measure of ∠C will be 20°