in a triangle abc, 2 angle A= 3 angle B= 6 angle C,calculate angle B
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2angleA=3angleB=6angleC
=angleA+angleB+angleC=180(angle sum property) ----eq1
let x=2angleA=3angleB=6angleC
x=2angleA. x/2=angleA. ----eq2
x=3angleB. x/3=angleB. ----eq3
x=6angleC. x/6=angleC. ----eq4
substituting eq2,3,4 in eq1
x/2+x/3+x/6=180
Lcm=6
3x+2x+x/6=180
6x=180×6
6x=1080
x=180------eq 5
substituting eq 5 in eq 2,3,4
angleA=x/2=90
angleB=x/3=60
angleC=x/6=30
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Answer:
a+b+c=180
3+6+c=180
c=180-6-3
c=171
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