Question

in a triangle ABC 2ac sin1/2(A-B+C)=
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Answer 1

Answer:

a²-b²+c²

Explanation:

We know that,

A + B + C = 180°

A + C - B = 180 - 2B

now

2ac sin (1/2(A-B+C))

=2ac sin (90 °-B)

=2ac cos B =(2 ac *(a²-b²+c²))/2ac

= a²-b²+c²

Please mark it brainliest!

Answer 2

Answer:

Answer:a2-b2+c2

Explanation:

its correct answer ✔️✔️