in a triangle ABC.a=120 dec and b=2angle c find the angle b and c
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Answered by
7
We have,
∠A=120 ∘ and AB=AC⇒∠B=∠C
But, ∠A+∠B+∠C=180∘
∴120 ∘ +∠B+∠B=180 ∘
⇒2∠B=60 ∘
⇒∠B=30 ∘
⇒∠C=∠B=30 o
Answered by
0
Step-by-step explanation:
<A +<B+<C = 180
120 +2 *c + c =180
3^c =180 -120
=60 =3^c
<c =60/3=20 degree
<B =20 *2 =40
angle B =40
angle C = 20
120 +40 +20 =180 degree
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